j^2+7j+10=0

Simple and best practice solution for j^2+7j+10=0 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for j^2+7j+10=0 equation: 



j^2+7j+10=0

a = 1; b = 7; c = +10;
Δ = b2-4ac
Δ = 72-4·1·10
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-3}{2*1}=\frac{-10}{2}
=-5
$


$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+3}{2*1}=\frac{-4}{2}
=-2
$

See similar equations:

| 9a+6=15 | | 125=5b | | 72=18y-9y | | 5x+1+84=180 | | 5x+18=3x+12 | | 24x+4=52 | | 11x+7=6x-3 | | 4r^2=8r=0 | | 9x+4=6x+6-3x | | 5x^2=200-15x | | -25=-5x-3+7x | | 1/12x-1/12=1/8+1/6-1/6x | | 2x-x-2/4=5x/8+5 | | 3(z+5)+3z=135 | | 5(x+3)=2(x+9 | | 5x3=25 | | 16=-2c–6c | | -4=-r+1/3 | | 5x=12=3x-6 | | 9x=6=32 | | 8x+9=3x+15 | | -3=-9+u/6 | | 5.5x+33=57 | | x-78=27 | | -3u+24=9(u-4) | | (1/5)^2x=15625 | | b+55=16 | | x-78=x | | -24=-5a–3a | | x(1+0.08)^17=150000 | | |z-3|=8 | | -u/2-15=-16 |

Equations solver categories